simonreiff 18 minutes ago
When I think about Langlands, I think it is the power of equivalence over equality that shockingly allows us to connect the discrete world of the natural numbers (or Q) with the world of the continuous (R or C), across disparate branches of mathematics. The Modularity Theorem (every elliptic curve over Q is modular) is the foundational idea and at every step along the way, we obtain evidence of more remarkable equivalences: The conductor N of an elliptic curve versus the level N of certain congruence groups; the point count deficiency (p'th Hecke eigenvalue) of a curve and the p'th coefficient of the Fourier q-expansion; Galois reciprocity showing an equivalence between the traces of Frobenius elements acting on a cohomology, and the eigenvalues of Hecke operators; Ribet's theorem about level lowering; etc. Time and again, the theme in Langlands is that equivalence relationships make it possible for us to reason why two intricate mathematical structures that seem completely foreign are actually "essentially the same" -- not equal, but equivalent.
jjtheblunt 2 hours ago
I had (and donated to an engineering library in Urbana) a book about just this from the early 90s. I tried finding it on Amazon but no such luck.
This was a recurrent tool at
https://en.wikipedia.org/wiki/University_of_Illinois_Center_...
lanstin an hour ago
renyicircle an hour ago
I get that it's hard to wrap one's head around the Langlands program but I'd love to see at least more exposition on the following statement:
>inventing the Euclidean algorithm is essentially equivalent to inventing unique prime factorization
srean 26 minutes ago
I thought this was obvious, like which is the better editor vi or whatever that other one was.
More here
https://web.archive.org/web/20160615205452/http://www2.slgb.... Section 2
https://news.tulane.edu/pr/researchers-solve-ancient-mystery...
https://www.ias.ac.in/article/fulltext/reso/007/10/0006-0022
paulpauper 40 minutes ago
This is not what the Langlands program is